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the product of (3+ square root of 5) and (3-square root of 5 )
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4
how did you get tht
yes, its factored as a difference of squares so you get a^2 which is 3 squared (9) minus root of five squared which is five so 9-5=4
\[(3+\sqrt{5})(3-\sqrt{5})\]square the 3s and the root 5 9-5=4
(3-V5)*(3+V5) it is in the form of (a-b)(a+b) = (a^2-b^2)
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