Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

i need help someone wanna help me???

OpenStudy (anonymous):

what's up?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

post your question and find out

OpenStudy (anonymous):

Maybe...... I dont know just maybe

OpenStudy (anonymous):

What's your question?

OpenStudy (anonymous):

(4u^4/8v^3) ^3

OpenStudy (anonymous):

2. 9x-7=

OpenStudy (anonymous):

sorry its 9x ^-7

OpenStudy (anonymous):

distribute the ^3 to both top and bottom and to each number and variable \[4^{3} \times u ^{4\times 3} \over 8^{3}\times v ^{3\times 3}\]now simplify \[64u ^{12} \over 512v ^{9}\]\[u ^{12} \over 8v ^{^{9}}\]

OpenStudy (anonymous):

(4u^4/8v^3)^3= (4/8)*(4/8)*(4/8)=64/512 64/512=1/8 u^12/8^9

OpenStudy (anonymous):

excuse me I mean u^12/8v^9

OpenStudy (anonymous):

9x^-7

OpenStudy (anonymous):

are you sure you're not looking at the wrong answer or question? there's no x in the question you gave us. the answer should have a u and a v in it.

OpenStudy (anonymous):

i typed in sheg answer i need the 9x one

OpenStudy (anonymous):

Im replying to the first one. I havnt even looked at the 2nd one

OpenStudy (anonymous):

is the 9x in parenthesis?

OpenStudy (anonymous):

nope. just the way i wrote it

OpenStudy (anonymous):

fast plz i have 45 mins to do 20 qs. :(

OpenStudy (anonymous):

sorry sheg you messed up somewhere.

OpenStudy (anonymous):

okay, then the 9 stays on top, and the x goes to the bottom where the exponent will be positive so it should look like this: \[9 \over x ^{7}\]

OpenStudy (anonymous):

only answers. thats it

OpenStudy (anonymous):

next Q?

OpenStudy (anonymous):

im pretty sure im suposed to get a one number answer. like maybe - something

OpenStudy (anonymous):

the 2nd one is easy. its already solved you just have to calculate what 2^9 is

OpenStudy (anonymous):

u^12/512v^9

OpenStudy (anonymous):

(2x^3) (2x^2) =

OpenStudy (anonymous):

4x^5

OpenStudy (anonymous):

you should know how to add and subtract exponents atleast. This isnt going to do you any good for people to solve these for you.

OpenStudy (anonymous):

(x^2y^4)^-2=

OpenStudy (anonymous):

i know but im in a rush cause these arent stickin in my head. i have a learning disability for numbers and trust me, if i didnt have to i wouldnt be on here. if u arent willing to help then leave and dont waste my time. agent.

OpenStudy (anonymous):

can you retype that last question?

OpenStudy (anonymous):

(x^2y^4)^-2=

OpenStudy (anonymous):

x^-4y^4

OpenStudy (anonymous):

(-2)^7/(-2)^5=

OpenStudy (anonymous):

4

OpenStudy (anonymous):

(x+4)(x+6)= hey would this be x12?

OpenStudy (anonymous):

i mean 10

OpenStudy (anonymous):

5x^8y^6/15x^8y^4

OpenStudy (anonymous):

hello? did everyone leave? :_

OpenStudy (anonymous):

1/3 x^8y^6 - 8y^4

OpenStudy (saifoo.khan):

can u post that again please..?

OpenStudy (anonymous):

(3x^2+1)(2x^2+6)=

OpenStudy (saifoo.khan):

We are going to use FOIL in this question.

OpenStudy (anonymous):

\[6x ^{2}+20x+6\]

OpenStudy (anonymous):

thank u again liamarie! i have only 12 to go

OpenStudy (saifoo.khan):

Right,

OpenStudy (anonymous):

^he's right

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

sorry guys this next ones a biggie :( here it is.....

OpenStudy (anonymous):

(x^-1y^5z^0/x^2y^8)

OpenStudy (anonymous):

oh and after the bracket at the end there is an exponent 2 after it

OpenStudy (anonymous):

(x^-1y^5z^0/x^2y^8)^2

OpenStudy (anonymous):

\[1 \over x ^{4y ^{8+2y ^{5}}}\]

OpenStudy (anonymous):

the 2y^5 should should be the 4y^8

OpenStudy (anonymous):

-9a^8b/3ab^8=

OpenStudy (anonymous):

28 mins left !

OpenStudy (anonymous):

\[a ^{8b-1} \over 27b ^{8}\]

OpenStudy (anonymous):

how many more?

OpenStudy (anonymous):

9? i think

OpenStudy (anonymous):

(p^14q^2) (p^13q)

OpenStudy (anonymous):

next one is: 8x^-5=

OpenStudy (anonymous):

3rd one is : (a^5b^-8)^-5/(2a^2b^-1)^-2

OpenStudy (anonymous):

p^(14(q^2)-13q)

OpenStudy (anonymous):

8/x^5

OpenStudy (anonymous):

\[4b ^{38} \over a ^{21}\]

OpenStudy (anonymous):

thank u! (-5a^5b^7c)^2

OpenStudy (anonymous):

next one: the expression (7y-1)^2 equals _______________

OpenStudy (anonymous):

\[25a ^{10}b ^{14c}\]

OpenStudy (anonymous):

49y^2-14y+1

OpenStudy (anonymous):

5x^6y^3z^0/-4x^6y^7z^5=

OpenStudy (anonymous):

(4a^4b^-5)^3=

OpenStudy (anonymous):

ill let you know my score after i submit it. i have three more to go! :)

OpenStudy (anonymous):

5/-4y^4z^5 can you go back and change any of them?

OpenStudy (anonymous):

64a^12/b^15

OpenStudy (anonymous):

no. yeah but i have 7 mins

OpenStudy (anonymous):

im guessing the last three cuz im outta time

OpenStudy (anonymous):

kay what are the rest of them?

OpenStudy (anonymous):

im guessing the last three cuz im outta time

OpenStudy (anonymous):

how'd you do?

OpenStudy (anonymous):

8/20 are correct. thank you for your help. good thing my teacher takes the best five out of six tests i do and marks them. lol. thank you so much or i woulda had them all wrong lol

OpenStudy (anonymous):

sorry i couldn't help you more. if you ever need help you can just e-mail me if you'd like or facebook me

OpenStudy (anonymous):

ok whats yourfacebook? my name is molliee nairnn on facebook. ive gott

OpenStudy (anonymous):

lia gianfortone

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!