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Mathematics 7 Online
OpenStudy (anonymous):

factor completely b^2+36-12b

OpenStudy (anonymous):

\[(b-6)^{2}\]

OpenStudy (anonymous):

(b-6)^2

OpenStudy (anonymous):

i'm gonna have to start paying you guys lol

jimthompson5910 (jim_thompson5910):

b^2-12b+36 b^2-6b-6b+36 (b^2-6b)+(-6b+36) b(b-6)+(-6b+36) b(b-6)-6(b-6) (b-6)(b-6) (b-6)^2 So b^2-12b+36 factors to (b-6)^2 In other words, b^2-12b+36=(b-6)^2

OpenStudy (anonymous):

sounds good

OpenStudy (anonymous):

for me too it sounds cool

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