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Mathematics 18 Online
OpenStudy (anonymous):

(-x^3y^2)^2

OpenStudy (diyadiya):

x^6y^4

OpenStudy (lalaly):

\[\large{(xy)^{m}} = (x^my^m)\]

OpenStudy (anonymous):

x^6y^4 is wrong. Unless, the problem is (-x^(3y^2))^2.

OpenStudy (anonymous):

You need to multiple (-x^3y^2) by itself. So, you get (-1) * (-1) * (x^3 * x^3) * (y^2 * y^2). Simplify for the real answer.

OpenStudy (diyadiya):

\[(-x^3 y^2)^2=(-x^3)^2(y^2)^2=x^6y^4\]

OpenStudy (lalaly):

@GT your answers simplifies to Diyadiyas answer

OpenStudy (lalaly):

answer*

OpenStudy (lalaly):

\[\large{x^3 \times x^3 = x^{3+3} = x^6}\]

OpenStudy (lalaly):

\[\large{y^2 \times y^2 } = y^4\]

OpenStudy (anonymous):

without a "*" in between, hard to see. I read it as x^(6y^4). :-)

OpenStudy (lalaly):

oh okay :D

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