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Mathematics 16 Online
OpenStudy (anonymous):

matrix questions please help, I attached a .png file and description of what I need to accomplish under it.

OpenStudy (anonymous):

OpenStudy (anonymous):

Please note that the notation that looks like absolute value, means to take the determinant. So in both problems you are to take the determinant. The first one is an identity so you are to take the determinant of the matrix on the left and then simplify it so that it becomes the expression on the right. It is an exercise in algebra. The second problem is an equation, so after taking the determinant, you are to solve the remaining equation and find the value(s) for x.

OpenStudy (anonymous):

[b c] - [a c] + [a b] [b^2 c^2] [a^2 c^2] [a^2 b^2] =(bc^2 -b^2 c)-(ac^2 -ca^2)+(ab^2 -ba^2) =bc^2 -b^2 c-ac^2 +ca^2+ab^2 -ba^2 (to be check) now from (a-b)(b-c)(c-a) (a-b)(b-c)=ab+bc-b^2 -ac then =(a-b)(b-c)(c-a)=(ab+bc-b^2 -ac)(c-a) =abc+ bc^2 -b^2 c-ac^2 +ca^2+ab^2 -ba^2 -abc = bc^2 -b^2 c-ac^2 +ca^2+ab^2 -ba^2 (check)

OpenStudy (anonymous):

any question xixe?

OpenStudy (anonymous):

2) [x o c] [-1 x b] [0 -1 a] =x(ax+b)-0(-a-0)+c(1-0) =ax^2 +bx+c ans

OpenStudy (anonymous):

x=[-b -+sqrt(b^2 -4ac)]/2a

OpenStudy (anonymous):

on the first matrix, what did you do with the 1's ?

OpenStudy (anonymous):

ok if start on the top column its 1(bc^2 -b^2 c)-1(ac^2 -ca^2)+1(ab^2 -ba^2)

OpenStudy (anonymous):

ahh i see you just didnt put them there cause they dont make a difference to the equation?

OpenStudy (anonymous):

+ - + - + - + - +

OpenStudy (anonymous):

you can start also on column 1 with 1(bc^2)-a(c^2 -b^2) +a^2 (c-b)

OpenStudy (anonymous):

and you will arrived on the same answer

OpenStudy (anonymous):

and when you put (to be checked) and (check) are those the answers i can plug into a calculator to check if its correct? I appreciate your help, and taking the time to explain this to me.

OpenStudy (anonymous):

the idea here is you can start anywhere you want.. you can start in the 2nd column or the 3rd column if you want

OpenStudy (anonymous):

practise that on number 2) its easier there

OpenStudy (anonymous):

awesome, thank you for your help mate.. i really appreciate it :)

OpenStudy (anonymous):

yes you can check on your calc if they are all numbers

OpenStudy (anonymous):

yw ....good luck now

OpenStudy (anonymous):

thanks lol, i will need it with this professor assigning questions like this

OpenStudy (anonymous):

ok

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