Passes through (3,1) and perpendicular to graph of y=1/2x+3?
Explain. Passes through (3,1) and perpendicular to graph of y=1/2x+3?
Explain. @Mathematics

Question

anonymous · Answer

Perpendicular slopes will equal -1 so to find the perpendicular slope of 1/2 you do this $$\frac{1}{2} + x = -1$$ Solve for x and you get the perpendicular slope of -2

anonymous · Answer

now that you have a point on the graph and a slope, use the point slope formula

anonymous · Answer

$$y - 1 = -2(x - 3)$$ solve for y $$y = -2x + 7$$

anonymous · Answer

Thanks, I just don't understand this stuff.. My teacher is WACK and won't explain it to me.. Thank you though!

anonymous · Answer

Just remember that perpendicular slopes add up to -1.. or the easy way is to do the negative reciprocal. Reciprocal means to flip the fraction and then all you have to do is negate it. So if you have a slope of 3/2 and you want the perpendicular slope all you do is flip the fraction... 2/3.. then negate it.. so the slope perpendicular to 3/2 would be -2/3. Understand??

anonymous · Answer

Yeah I think I got it! My teacher just needs to teach it like that! THANKS!