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derivative of csc x derivative of csc x @Mathematics
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the answer is -csc(x)cot(x). I'll provide the steps in a second, wanna make it look neat.
\[\csc(x)=1/\sin(x)\] same as \[\sin(x)^-1\] take the derivative =\[-\sin^-2(\cos(x))\] or \[-\cos(x)/\sin^2(x)\] split it up, \[-1/\sin(x)*(\cos(x))/(\sin(x))\] which leads us to \[-\csc(x)*\cot(x)\]
There are a couple other ways you can prove it, that's just the simplest.
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