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solve by substitution method. 4x+9y=-5 x=1-3y
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in the top equation, fill in 1-3y for x, which gives \[4\times \left( 1-3y \right)+9y =- 5\]
gives 4 - 3y = -5, so y =3
then fill is 3 for y in the lower equation
which gives \[x = 1-3\times3=-8\]
it says i need an ordered pair so it would be y=3 and what does x=?
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you take the lower equation: x=1-3y, and substitue y with the number you got from the top equation (y=3)
ok thanks
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