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when dividing 6^-9/6^10 do you just divide the square root of both these?
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6^ -9 / 6^10 = 6^(-9-10) = 6^-19
you subtract the exponents
how come you dont do anything with the integers?
it is 6^-9/6^10 = 6^(-9-10) = 6^(-19)
you dont because its a the same integer (6) - the law of exponents take a simple example x^3 / x^2 = x^1 or x
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ok just making sure and thanks
yw
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