How do you get the factors of x^3 - 12x^2 + 32x -120

There can be 1 positive real root and 2 complex roots. How would you find them? How do you get the factors of x^3 - 12x^2 + 32x -120

There can be 1 positive real root and 2 complex roots. How would you find them? @Mathematics

Question

How do you get the factors of x^3 - 12x^2 + 32x -120

There can be 1 positive real root and 2 complex roots. How would you find them? How do you get the factors of x^3 - 12x^2 + 32x -120

There can be 1 positive real root and 2 complex roots. How would you find them? @Mathematics

anonymous · Answer

I used the synthetic division, and got 10. But I dont know if that is right

lukecrayonz · Answer

Roots are x=10, 1+isqrt(11), 1-isqrt(11).

Factored it is (x-10)(x^2-2x+12)

anonymous · Answer

Yeah I got x = 10, but I got  1 ± 2√11

anonymous · Answer

Ok my bad I got 1±2i√11