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OpenStudy (anonymous):

my question is: cos^2 x = ???

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OpenStudy (anonymous):

what are you finding?

OpenStudy (anonymous):

I want to find " integral 16 cos^2 x

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

Let me see.

OpenStudy (anonymous):

Let me see.

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OpenStudy (anonymous):

8(x+sin(x)cos(x))

OpenStudy (anonymous):

ahaa.. SURE !!? My teacher will kill me hahaha

OpenStudy (anonymous):

cos2x = 2cos square X -1

OpenStudy (anonymous):

so cos square X = (1+cos2X)/2

OpenStudy (anonymous):

srinu7j ; not cos 2x ... its( cos ^2) x

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OpenStudy (anonymous):

Let me see.

OpenStudy (anonymous):

yeah

OpenStudy (agreene):

\[\int16cos^2(x)dx\] \[=16 \int cos^2(x) dx\] \[ = 16 \int (1/2 cos(2 x)+1/2) dx\] \[ = 16 \int 1/2 dx + 8 \int cos(2 x) dx\] For the integrand cos(2 x), substitute u = 2 x and du = 2 dx: \[ = 4 \int cos(u) du+16 \int 1/2 dx\] \[= 4 \int cos(u) du+8 x\] \[ = 4 sin(u)+8 x+c\] Substitute back for u = 2 x: \[= 8 x+4 sin(2 x)+c\] \[\huge = 8 (x+sin(x) cos(x))+c\]

OpenStudy (anonymous):

I will repate my Q: INTEGRAL 16 cos^2|dw:1319605597473:dw| x

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