Question

my question is: cos^2 x = ???

Answer 1

what are you finding?

Answer 2

I want to find " integral 16 cos^2 x

Answer 3

oh ok

Answer 4

Let me see.

Answer 5

Let me see.

Answer 6

8(x+sin(x)cos(x))

Answer 7

ahaa.. SURE !!? My teacher will kill me hahaha

Answer 8

cos2x = 2cos square X -1

Answer 9

so cos square X = (1+cos2X)/2

Answer 10

srinu7j ; not cos 2x ... its( cos ^2) x

Answer 11

Let me see.

Answer 12

yeah

Answer 13

\[\int16cos^2(x)dx\]
\[=16 \int cos^2(x) dx\]
\[ = 16 \int (1/2 cos(2 x)+1/2) dx\]
\[ = 16 \int 1/2 dx + 8 \int cos(2 x) dx\]
For the integrand cos(2 x), substitute u = 2 x and du = 2 dx:
\[ = 4 \int cos(u) du+16 \int 1/2 dx\]
\[= 4 \int cos(u) du+8 x\]
\[ = 4 sin(u)+8 x+c\]
Substitute back for u = 2 x:
\[= 8 x+4 sin(2 x)+c\]
\[\huge = 8 (x+sin(x) cos(x))+c\]

Answer 14

I will repate my Q:
INTEGRAL 16 cos^2 x