Find integers c≠0, a, b, m such that the solution set of ax≡b (mod m) is different from the solution set of cax≡cb (mod m) Find integers c≠0, a, b, m such that the solution set of ax≡b (mod m) is different from the solution set of cax≡cb (mod m) @Mathematics

Modern Algebra - that looks like fun!

Haha.. any suggestions?

yes I believe all that happened is c got multiplied by both sides. When you study modern algebra recall your regular algebra except not using mod you can say silly stuff like 1+1=3 as long as you can justify it using a mod. My Modern Algebra professor got mad once his child got some problem incorrect like 1+1=3 so he was going to go argue with the teacher because he knew he could prove it in some mod. Anyways it was a corny math joke we got but I am not sure the elementary teacher would have got it or appreciated it.

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