Ask your own question, for FREE!
Mathematics 26 Online
OpenStudy (anonymous):

Explain why the following is false: If (a,b) gives rise to a (constrained) relative extrema of f subject to the constraint g(x,y)=0, then (a,b) also gives rise to the unconstrained relative extrema of f. Explain why the following is false: If (a,b) gives rise to a (constrained) relative extrema of f subject to the constraint g(x,y)=0, then (a,b) also gives rise to the unconstrained relative extrema of f. @Mathematics

OpenStudy (anonymous):

we are studying Lagrange Multipliers if that helps :)

OpenStudy (zarkon):

easy to see by an example if \[f(x,y)=x^2+y^2\] then is is clear that f(x,y) has no max but if we constrain on the plane x+y+z-1=0 it is easy to see that there is an absolute max

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!