Question

Using the function y = x^3�----------4, and starting values x0 = 1 and x1 = 2 use the bisection method to compute 2^(2^3) up to 2 decimal places. Repeat the exercise with the same initial data using the secant method. Repeat it for three steps and compare your approximation to the bisection method.

Answer 1

thats just meant to be (x^3)-4

Answer 2

and 2^(2/3) is what needs to be computed