Using the function y = x^3�----------4, and starting values x0 = 1 and x1 = 2 use the bisection method to compute 2^(2^3) up to 2 decimal places. Repeat the exercise with the same initial data using the secant method. Repeat it for three steps and compare your approximation to the bisection method.
thats just meant to be (x^3)-4
and 2^(2/3) is what needs to be computed
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