9x^2-30x-25

and what ?

=0, BTW

what is the discriminant ?

Thanks

@JaredP: \[ 9x ^{2} - 30x - 25 \neq (3x - 5) (3x - 5) \] but \[ 9x ^{2} - 30x + 25 = (3x - 5) (3x - 5) \]

You should understand it though, getting answers on here is a waste of everyones time. Go to wolfram alpha if you just want the answer. If you don't understand how I got that answer than just say so.

@JaredP: The OP's equation do not have any real solution.

oh crap your right! you have to use quadratic equation then.

What JaredP means that you should us quadratic fromula which will give you : \[ \left\{\left\{x= \frac{5}{3} \left(1-\sqrt{2}\right)\right\},\left\{x=\frac{5}{3} \left(1+\sqrt{2}\right)\right\}\right\} \]

In your case \[ax^2 - bx - c\] \[(-b \pm \sqrt{b^2-4ac})/2a\] so in your case a=9, b = -30 and c=-25 Did I get that right FoolForMath?

http://www.wolframalpha.com/input/?i=quadratic+theory this site is really amazing

:)

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