In the figure below, CE and AB are parallel and CE is the bisector of angle ACD. If angle ACD measures 110 degrees, what is the measure of arc BC?
Also please explain how its part of my homework
Never really dealt with arcs before but I'll take a shot: angle ACD is 110 so angle ACE is 55 since it has been bisected. angle BAC must also be 55 since CE || AB (alternate interior angles) angle BAC is going to be half the angle of the arc since it is at the circumference and not the center. So therefore arc BC measures 110 degrees
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