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OpenStudy (anonymous):
Homogeneity of a function:
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OpenStudy (anonymous):
OpenStudy (amistre64):
thats just awful .... i almst lost an eye looking at that
OpenStudy (amistre64):
if f(ax,ay) = f(x,y) then its homogenous
OpenStudy (anonymous):
That part i am aware. The questions is how do i arrange the denominator? That one plus is ruin everything.
OpenStudy (amistre64):
i recall something that might work out; something to do with y=vx
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OpenStudy (amistre64):
which might be able to be adapted into this
OpenStudy (amistre64):
x2 = c(x1) but this has to do with differential equations so im not sure how to apply it here
OpenStudy (anonymous):
Well, me neither. Thanks anyway.
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