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OpenStudy (anonymous):

Can someone help me with logarithms?

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OpenStudy (anonymous):

\[\log_{32}4= 2/5 \]

OpenStudy (anonymous):

I could try,what is the problem?

OpenStudy (anonymous):

Ho would you solve for that is 2/5 was x?

OpenStudy (anonymous):

ERR???? Please explain your problem :)

OpenStudy (anonymous):

How would you solve for x , if x was 2/5 *

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OpenStudy (anonymous):

\[\log_{32}4= x \]

OpenStudy (anonymous):

\[ \log_{32}4= x \Rightarrow 2^2 = 2^{5x } \Rightarrow x= \frac25\]

OpenStudy (anonymous):

I don't see how you got 2^2

OpenStudy (anonymous):

\[ 4=2^2 \]

OpenStudy (anonymous):

what abot 2^5x?

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OpenStudy (anonymous):

Okay first answer me what does \[ \log_a b =y \] implies ?

OpenStudy (anonymous):

\[a^y= b\]

OpenStudy (anonymous):

Good now \[ 32 = 2^5 \] got it ?

OpenStudy (anonymous):

okay so you just put them in exponential form and solved for X while using the one-on-one property? \[2 = 5x?\]

OpenStudy (anonymous):

yeps, If a^b = a^c then b = c.

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OpenStudy (anonymous):

Awesome, great answer. Thanks

OpenStudy (anonymous):

Welcome,Glad to help :) Now click the good answer :P

OpenStudy (anonymous):

hhahaha I was just about to!

OpenStudy (anonymous):

;)

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