Mathematics 22 Online
OpenStudy (anonymous):

Can someone help me with logarithms?

OpenStudy (anonymous):

$\log_{32}4= 2/5$

OpenStudy (anonymous):

I could try,what is the problem?

OpenStudy (anonymous):

Ho would you solve for that is 2/5 was x?

OpenStudy (anonymous):

OpenStudy (anonymous):

How would you solve for x , if x was 2/5 *

OpenStudy (anonymous):

$\log_{32}4= x$

OpenStudy (anonymous):

$\log_{32}4= x \Rightarrow 2^2 = 2^{5x } \Rightarrow x= \frac25$

OpenStudy (anonymous):

I don't see how you got 2^2

OpenStudy (anonymous):

$4=2^2$

OpenStudy (anonymous):

what abot 2^5x?

OpenStudy (anonymous):

Okay first answer me what does $\log_a b =y$ implies ?

OpenStudy (anonymous):

$a^y= b$

OpenStudy (anonymous):

Good now $32 = 2^5$ got it ?

OpenStudy (anonymous):

okay so you just put them in exponential form and solved for X while using the one-on-one property? $2 = 5x?$

OpenStudy (anonymous):

yeps, If a^b = a^c then b = c.

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

hhahaha I was just about to!

OpenStudy (anonymous):

;)

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