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OpenStudy (anonymous):
Can someone help me with logarithms?
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OpenStudy (anonymous):
\[\log_{32}4= 2/5 \]
OpenStudy (anonymous):
I could try,what is the problem?
OpenStudy (anonymous):
Ho would you solve for that is 2/5 was x?
OpenStudy (anonymous):
ERR???? Please explain your problem :)
OpenStudy (anonymous):
How would you solve for x , if x was 2/5 *
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OpenStudy (anonymous):
\[\log_{32}4= x \]
OpenStudy (anonymous):
\[ \log_{32}4= x \Rightarrow 2^2 = 2^{5x } \Rightarrow x= \frac25\]
OpenStudy (anonymous):
I don't see how you got 2^2
OpenStudy (anonymous):
\[ 4=2^2 \]
OpenStudy (anonymous):
what abot 2^5x?
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OpenStudy (anonymous):
Okay first answer me what does \[ \log_a b =y \] implies ?
OpenStudy (anonymous):
\[a^y= b\]
OpenStudy (anonymous):
Good now \[ 32 = 2^5 \] got it ?
OpenStudy (anonymous):
okay so you just put them in exponential form and solved for X while using the one-on-one property? \[2 = 5x?\]
OpenStudy (anonymous):
yeps, If a^b = a^c then b = c.
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OpenStudy (anonymous):
Awesome, great answer. Thanks
OpenStudy (anonymous):
Welcome,Glad to help :) Now click the good answer :P
OpenStudy (anonymous):
hhahaha I was just about to!
OpenStudy (anonymous):
;)
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