Question

Can someone help me with logarithms?

Answer 1

\[\log_{32}4= 2/5 \]

Answer 2

I could try,what is the problem?

Answer 3

Ho would you solve for that is 2/5 was x?

Answer 4

ERR???? Please explain your problem :)

Answer 5

How would you solve for x , if x was 2/5 *

Answer 6

\[\log_{32}4= x \]

Answer 7

\[ \log_{32}4= x \Rightarrow 2^2 = 2^{5x } \Rightarrow x= \frac25\]

Answer 8

I don't see how you got 2^2

Answer 9

\[ 4=2^2 \]

Answer 10

what abot 2^5x?

Answer 11

Okay first answer me what does \[ \log_a b =y \] implies ?

Answer 12

\[a^y= b\]

Answer 13

Good now \[ 32 = 2^5 \] got it ?

Answer 14

okay so you just put them in exponential form and solved for X while using the one-on-one property?
\[2 = 5x?\]

Answer 15

yeps, If a^b = a^c then b = c.

Answer 16

Awesome, great answer. Thanks

Answer 17

Welcome,Glad to help :)


Now click the good answer :P

Answer 18

hhahaha I was just about to!

Answer 19

;)