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Can someone help me with logarithms?
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\[\log_{32}4= 2/5 \]
I could try,what is the problem?
Ho would you solve for that is 2/5 was x?
ERR???? Please explain your problem :)
How would you solve for x , if x was 2/5 *
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\[\log_{32}4= x \]
\[ \log_{32}4= x \Rightarrow 2^2 = 2^{5x } \Rightarrow x= \frac25\]
I don't see how you got 2^2
\[ 4=2^2 \]
what abot 2^5x?
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Okay first answer me what does \[ \log_a b =y \] implies ?
\[a^y= b\]
Good now \[ 32 = 2^5 \] got it ?
okay so you just put them in exponential form and solved for X while using the one-on-one property? \[2 = 5x?\]
yeps, If a^b = a^c then b = c.
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Awesome, great answer. Thanks
Welcome,Glad to help :) Now click the good answer :P
hhahaha I was just about to!
;)
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