Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

If y^5+xy=2x-4, find dy/dx

OpenStudy (anonymous):

ok why not? the derivative of \[f^5(x)\] is \[5f^4(x)\times f'(x)\] by the chain rule, meaning the derivative of \[y^5\] is \[5y^4y'\] as above

OpenStudy (anonymous):

the derivative of \[xf(x)\] is \[f(x)+xf'(x)\] by the product rule, so the derivative of \[xy\] is \[y+xy'\] and so on

OpenStudy (anonymous):

Confused again...

OpenStudy (anonymous):

oh! Okay! I see...so how do i do the other half of the equation?

OpenStudy (anonymous):

for the xy part, use product rule

OpenStudy (anonymous):

1.y+xy'

OpenStudy (anonymous):

for the right hand side =2

OpenStudy (anonymous):

if u combine all these u get 5y^4y'+y+xy'=2 y'(5y^4+x)=2-y y'=2-y/5y^4+x

OpenStudy (anonymous):

Thank you! That was the perfect reply...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
1 day ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
1 day ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!