can anyone help me on a quotient problem for Calculus on derivatives?

Question

anonymous · Answer

whats the prob?

anonymous · Answer

y=(cosx)/(1-sinx)  can you show the steps because I know I messed up somewhere but I just can extract exactly where.

amistre64 · Answer

what have you tried?

anonymous · Answer

u know the quotient rule?

amistre64 · Answer

$$[\frac{t}{b}]'=\frac{bt'-b't}{b^2}$$

anonymous · Answer

Yeah I do know the quotient rule.

anonymous · Answer

yes amistre, u definetly know this:)

amistre64 · Answer

;)

anonymous · Answer

ok Dandy, apply it for ur prb

anonymous · Answer

Hmmm remember when you solve trig problems in calculus you have to simplify them using trig identity like Pythagorean theorem and double angel formula etc before you can eve get the correct answer

anonymous · Answer

Well right now I'm at (-sinx+sin^2x-cosx+cos^2x)/(-sinx)^2

anonymous · Answer

and I tried simplifying witht he trig identities but I'm not sure if I am applying them accordingly

anonymous · Answer

y'=(1-sinx)(-sinx)-(cosx)(-cosx)/(1-sinx)^2

anonymous · Answer

ohhhhhhhhhhhhhhhhh I see what I did wrong

anonymous · Answer

=(-sinx+sin^2x+cos^2)/(1-sinx)^2=-sinx+1/(1-sinx)^2

anonymous · Answer

I did the derivative wrong for v, it should of been -cosx because 1 is a constant.

anonymous · Answer

yes :)

anonymous · Answer

okay I think i did another computation error. now I'm at the final stages and I have
 (-sinx+1)/(1-sinx)^2