Mathematics 90 Online OpenStudy (connor):

A man built a house costing 9 times as much as the lot on which it was built. If the lot cost \$5000 less than 1/6 the cost of the house. What was the cost of each? OpenStudy (anonymous):

Price of lot is 1/9 the price of house. $1/9 = 1/6 -5000$ $5000 + 1/9 = 1/6$ $1/6-1/9=5000$ $1/18 = 5000$ Therefore 2/18 = 1/9 = 10000 = Price of lot Price of house = 10000*9= 90000 OpenStudy (anonymous):

Solve the following equations for house and lot:$\left\{\text{house} \text{ = } 9*\text{lot},\text{ lot }\text{=} \frac{1}{6}\text{ house}-5000\right\}$$\{\text{lot}=\text{\10000},\text{ house}=\text{\90000}\}$

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