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OpenStudy (anonymous):

how to derive this formula, integrate a^(mx+n)?

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OpenStudy (anonymous):

I assume you're integrating for \(x\), and that \(a, m\) and \( n\) are real numbers. If so, then substitute \(u=mx+n \implies du=mdx\). The integral becomes: \(\frac{1}{m}\int a^u du=\frac{1}{m}\frac{a^u}{\ln(a)}=\frac{1}{m}\frac{a^{mx+n}}{\ln(a)}.\)

OpenStudy (amistre64):

\[a^{mx+n}=a^{mx}*a^{n}\] might be useful

OpenStudy (amistre64):

why is the latex font type so tiny?

OpenStudy (anonymous):

I don't know! Do you know how I can make it bigger?

OpenStudy (amistre64):

\large and \Large can do it

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OpenStudy (amistre64):

\[\Large\frac{1}{m}\int a^u du=\frac{1}{m}\frac{a^u}{\ln(a)}=\frac{1}{m}\frac{a^{mx+n}}{\ln(a)}.\]

OpenStudy (anonymous):

\(\Large{\text{THANK YOU!}}\)

OpenStudy (amistre64):

\Huge is well, huge

OpenStudy (anonymous):

trying to do but it looks complicated...

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