Mathematics 63 Online OpenStudy (anonymous):

how to derive this formula, integrate a^(mx+n)? OpenStudy (anonymous):

I assume you're integrating for $$x$$, and that $$a, m$$ and $$n$$ are real numbers. If so, then substitute $$u=mx+n \implies du=mdx$$. The integral becomes: $$\frac{1}{m}\int a^u du=\frac{1}{m}\frac{a^u}{\ln(a)}=\frac{1}{m}\frac{a^{mx+n}}{\ln(a)}.$$ OpenStudy (amistre64):

$a^{mx+n}=a^{mx}*a^{n}$ might be useful OpenStudy (amistre64):

why is the latex font type so tiny? OpenStudy (anonymous):

I don't know! Do you know how I can make it bigger? OpenStudy (amistre64):

\large and \Large can do it OpenStudy (amistre64):

$\Large\frac{1}{m}\int a^u du=\frac{1}{m}\frac{a^u}{\ln(a)}=\frac{1}{m}\frac{a^{mx+n}}{\ln(a)}.$ OpenStudy (anonymous):

$$\Large{\text{THANK YOU!}}$$ OpenStudy (amistre64):

\Huge is well, huge OpenStudy (anonymous):

trying to do but it looks complicated...

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