Question

how to derive this formula, integrate a^(mx+n)?

Answer 1

I assume you're integrating for \(x\), and that \(a, m\) and \( n\) are real numbers. If so, then substitute \(u=mx+n \implies du=mdx\). The integral becomes:
\(\frac{1}{m}\int a^u du=\frac{1}{m}\frac{a^u}{\ln(a)}=\frac{1}{m}\frac{a^{mx+n}}{\ln(a)}.\)

Answer 2

\[a^{mx+n}=a^{mx}*a^{n}\] might be useful

Answer 3

why is the latex font type so tiny?

Answer 4

I don't know! Do you know how I can make it bigger?

Answer 5

\large and \Large can do it

Answer 6

\[\Large\frac{1}{m}\int a^u du=\frac{1}{m}\frac{a^u}{\ln(a)}=\frac{1}{m}\frac{a^{mx+n}}{\ln(a)}.\]

Answer 7

\(\Large{\text{THANK YOU!}}\)

Answer 8

\Huge is well, huge

Answer 9

trying to do but it looks complicated...