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Mathematics 69 Online
OpenStudy (anonymous):

3/x + 13/ x - 11 This is rational expressions, adding/subtracting them, Please help!

OpenStudy (anonymous):

Take the 1/x as a factor: (3+13-11x)/x=(16-11x)/x Can't really help much more than that since I've got nothing more to go on.

OpenStudy (anonymous):

If x is rational, this expression is rational. If x is not, neither is this.

OpenStudy (anonymous):

I got the answer, 16x - 33/x^2 - 11

OpenStudy (anonymous):

Could you re-write the expression with as many brackets as necessary? Just so we can see what the question is exactly.

OpenStudy (anonymous):

(3/x) + (13/ x - 11)

OpenStudy (anonymous):

13/(x-11)? Ah, my apologies.

OpenStudy (anonymous):

You have to make the denominators the same, so i multiplied the 3/x by x - 11 and then with 13/x-11 by x, in order to make it the same denominator. Im not sure if I did it right.. and it's ok i should have put te parentheses to make it less confusing

OpenStudy (anonymous):

You'll get (16x-33)/(x^2 -11x)

OpenStudy (anonymous):

Awesome so I kinda got it right i forgot the x on the 11, thank you very much :)

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