OpenStudy (anonymous):
On a sunny day,the daily profit, P dollars,of a popcorn vendor is modelled by the equation P= -60(x-4)^2 +120 where x is the price of a bag of popcorn. a) What should the price be to maximize daily profit ? b) What is the maximum amount of daily profit ? On a sunny day,the daily profit, P dollars,of a popcorn vendor is modelled by the equation P= -60(x-4)^2 +120 where x is the price of a bag of popcorn. a) What should the price be to maximize daily profit ? b) What is the maximum amount of daily profit ? @Mathematics
OpenStudy (anonymous):
a) dp/dx = -120(x-4) 0 = -120x + 480 120x= 480 x = 4 b) p(4) = -60(4-4)^2 + 120 = 120
OpenStudy (anonymous):
how did you get that ? like what are the steps ?
OpenStudy (anonymous):
a) derivative of p .. p'(x) and equate it to zero .. to find minimum/maximum b) plug the value from a to get the maximum amount of daily profit ..
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