Question

how do i find the equation of the parabola passing through the points (1,0), (3,0) and (2,-1)?

Answer 1

y=1x^2-4x+3

Answer 2

notice that your roots are at 1 and 3 so the vertex is centered between them at x=2 for starters

Answer 3

Also, it is concave up so therefore it is a Positive x^2

Answer 4

what is the procedure you did to find it precal?

Answer 5

multiply your roots and scale it to fit

Answer 6

I cheated. I just used my TI-84 + and did a regression

Answer 7

(x-1)(x-3) = x^2-4x +3

see how far off f(2) is from -1

Answer 8

That is your axis of symmetry

Answer 9

f(2) = 2^2 -4(2) + 3
= 4 -8 + 3
= -1

its not off so its just right