Question

In the fraction, assume that no denominator is 0. Simplify the expression.

(a^2b^3)^3/a^6b^6

Answer 1

(a^2b^3)^3 = (a^2)^3*(b^3)^3 = a^(2*3)*b^(3*3) = a^6b^9


So (a^2b^3)^3 = a^6b^9 (this is just the numerator)


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(a^2b^3)^3/(a^6b^6)


(a^6b^9)/(a^6b^6) ... simplify the numerator (see above)


Now subtract corresponding exponents


a^(6-6)b^(9-6)


a^0b^3


b^3



So (a^2b^3)^3/(a^6b^6) = b^3

Answer 2

Thank you!

Answer 3

np