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find the zeros f(x) = x3 – 12x2 + 28x – 9.
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f(x) = x^3 – 12x^2 + 28x – 9.
trial and error! :D
\[x=9\] \[x=\frac{1}{2}(3\pm\sqrt{5}\]
me, if would cheat. who wants to find the zeros of a cubic polynomial? http://www.wolframalpha.com/input/?i=x%5E3+%E2%80%93+12x%5E2+%2B+28x+%E2%80%93+9%3D0
oh look it is \[x=9,\frac{3\pm\sqrt{5}}{2}\]
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