Question

find the zeros f(x) = x3 – 12x2 + 28x – 9.

Answer 1

f(x) = x^3 – 12x^2 + 28x – 9.

Answer 2

trial and error! :D

Answer 3

\[x=9\]
\[x=\frac{1}{2}(3\pm\sqrt{5}\]

Answer 4

me, if would cheat. who wants to find the zeros of a cubic polynomial?
http://www.wolframalpha.com/input/?i=x%5E3+%E2%80%93+12x%5E2+%2B+28x+%E2%80%93+9%3D0

Answer 5

oh look it is
\[x=9,\frac{3\pm\sqrt{5}}{2}\]