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Find the equation of the tangent line to (x^2=4)y=8 at the point (-2,1)
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typo?
No, thats the exact question!
what does it mean \[(x^2=4)y=8\]?
(x^2-4)y=8, sorry! I didnt see the equal sign!
ok i got it . you can star wth \[y=\frac{8}{x^2-4}\] then take the derivative and find the slope at x = -2 you need the steps?
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hold the phone something else is wrong...
(-2,-1) is not on the graph.
if you replace x by -2 you get 0 on the left and 8 on the right, so there is a problem here
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