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why isn't 21^3*33*25^14 is a prime factorization?
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because 21 and 25 aren't prime numbers
oh and 33 as well
how about 105, is it a prime???
no since it's divisible by 3
105/3 = 35
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but 145 is a prime?
no, it's divisible by 5
since it ends with a 5
all right, got it. thanks for helping...
\[21^3*33*25^{14}\] \[=3^{3}*7^{3}*3*11*5^{28}\] \[=3^{4}*5^{28}*7^{3}*11\] now in prime factorization
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145 is not prime
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