hey all you algebra and higher people- I am writing a slope intercept form of an equation that is perpendicular to another equation. Example: (-3,-2), y=2x-4 i know how to do most of it. I'm wondering if i switch the slope from 2 to -1/2 now or late. Example: y=x+2 (-3,-2) -3=1*-2+b -3=-2+b +2 +2 -1=b y=-1x-1 or this: y=x+2 (-3,-2) -2=-1*-3+b -2=3+b -3 -3 -5=b you get how you have to make it a negative reciprocal to make it perpendicular? yeeah. which is right? hey all you algebra and higher people- I am writing a slope intercept form of an equation that is perpendicular to another equation. Example: (-3,-2), y=2x-4 i know how to do most of it. I'm wondering if i switch the slope from 2 to -1/2 now or late. Example: y=x+2 (-3,-2) -3=1*-2+b -3=-2+b +2 +2 -1=b y=-1x-1 or this: y=x+2 (-3,-2) -2=-1*-3+b -2=3+b -3 -3 -5=b you get how you have to make it a negative reciprocal to make it perpendicular? yeeah. which is right? @Mathematics
hehe same thinking! LOL -you change it "now" so you start and continue with a slope of -1/2 :)
so the second example?
As i can see.. in the second you put a slope of -1 right?
yes. I have been doing my problems wrong... :(
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