subtract, simplify if possible 3-z/z-8 - 6z-7/8-z
Sorry to ask. You are asking a series of similar questions. Can you try part way and see where you get stuck so someone can help you get better at solving such problems?
yeah i can try..
i just when i am doing math.. i will figure one problem out.. but when i go to the next one it is like i forget everything even when i am taking notes.. that is why i come here because ppl help me :D
math is my very worst subject.. I am a beast at everything else thou.
My point is that you need to be self dependent anyways. So, the best way to get to that point is by seeking help where you get stuck and making progress slowly until you get self dependent.
In this problem's case, you need to take the common denominator. Problem has z-8 and 8-z in the denominator(s). You can rather simplify the problem by converting the second one to -(z-8).
(3-z)/(z-8) - (6z-7)/(8-z) = (3-z)/(z-8) + (6z-7)/(z-8) (z-8) is the common denominator. So, simply add the numerators through and simplify.
see .. i honestly don't understand any of that..
See, the problem you posed is no different than an arithmetic problem dealing with fractions. For example how would you add 8/15 and 3/16? Same concept, except that you have algebra involved with variables and expressions.
so I am adding all the top together.. then adding all the bottom together??
You can't add the bottom together. You can take common denominator. (3-z)/(z-8) - (6z-7)/(8-z) =>(3-z)/(z-8) + (6z-7)/(z-8) => (3-z)+(6z-7)/(z-8) => (6z-z+3-7)/(z-8) => (5z-4)/(z-8)
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