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Mathematics 20 Online
OpenStudy (anonymous):

subtract 9/3t^2-3t - 4/3t-3= 5/3t-3? subtract 9/3t^2-3t - 4/3t-3= 5/3t-3? @Mathematics

OpenStudy (anonymous):

no, the downside is different, so need to make them the same

OpenStudy (anonymous):

times the upside and downside of 4/3t-3 by 3, then you can subtract

OpenStudy (anonymous):

downside is that the same has the denominator?

OpenStudy (anonymous):

yes, denominator, that is what i mean

OpenStudy (anonymous):

I was wrong , should times by t ,not 3

OpenStudy (anonymous):

so multiply both denominators by t?

OpenStudy (anonymous):

(4*t)/[(3t-3)*t]

OpenStudy (anonymous):

3t^2-3t=(3t-3)*t

OpenStudy (anonymous):

would it be 9-4z/3t(t-1)

OpenStudy (anonymous):

be careful: (9-4t)/[3t(t-1)]

OpenStudy (anonymous):

i have no clue where i got z lol

OpenStudy (anonymous):

is that correct though?

OpenStudy (anonymous):

try putting on parentheses in order to make it clear

OpenStudy (anonymous):

you are correct, but remember the parenteses

OpenStudy (anonymous):

ok thanks

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