IF two M&Ms are randomly selected with replacement before the second one is drawn what the is probability that the first M&M is green and the second one is blue?

Question

anonymous · Answer

if there are equal amounts of each color, and x number of colors.
then to draw a green one will be 1/x.
to draw a blue one will be 1/x. 
to draw them in that order, will be 1/x^2

anonymous · Answer

The chart is Red 15    Yellow 6   Green 10   Orange 11  Brown 9   Blue 6

anonymous · Answer

so greens probability is 10/57
blue is 6/57
green then blue is 60/(57^2)

anonymous · Answer

I am sorry what does it mean when you put (57^2) what does the ^ stand for?

anonymous · Answer

57 squared.

anonymous · Answer

57 raised to the power of 2

anonymous · Answer

So without reducing is the answer 60/3249?

anonymous · Answer

i dont think it reduces. 60/3249 might be all she wrote