Question

Can someone help me to find the limit of the function attached; x approaches to 1. Can someone help me to find the limit of the function attached; x approaches to 1. @Mathematics

Answer 1

aplly l'hospital;s rule

Answer 2

hey buddy as it 0/0 form apply l hospitals rule

Answer 3

I havent studied the l'hopilals rule. I dont think im allowed to use that technique

Answer 4

I think it has to do with derivatives. I havent learned derivatives yet

Answer 5

any other way?

Answer 6

ya

Answer 7

\[\frac{2x^{2n}-3x^{-2n}+1}{3x^{2n}+2x^{-2n}-5}\cdot\frac{x^{2n}}{x^{2n}}=\frac{2x^{4n}+x^{2n}-3}{3x^{4n}-5x^{2n}+2}\]\[=\frac{(2x^{2n}+3)(x^{2n}-1)}{(3x^{2n}-2)(x^{2n}-1)}=\frac{2x^{2n}+3}{3x^{2n}-2}\]
Now you can plug in x=1 directly.