Question

lim n approaches to infinte sinx^n lim n approaches to infinte sinx^n @Mathematics

Answer 1

A friend gave me this question.I am not sure even it is right

Answer 2

\[\lim_{x\rightarrow\infty}\sin(x^n)\]
is that the question?

Answer 3

yes

Answer 4

nope sorry.n approaches to infinte

Answer 5

As n approaches infinity, right?

Answer 6

yes

Answer 7

because x^n can be written as a fractional form for 0<x<1 that will have a limit of 0... I imagine you are going to end up with

lim -> 0 for 0<x<1
and
lim-> undefined for x>1
because lim x->infty [sin(x)] is undefined...

Answer 8

but I cant seem to remember how to show such things at the moment =/

Answer 9

alright.i kinda get it.thanks :)