Question

log_10(6 x-1) - log_10(x-1) = 1

Answer 1

Are you just putting up all your logarithm homework?

Answer 2

no these are the ones i don't understand how to do

Answer 3

log(x)-log(y)=log(x/y) as shown previously. 10^log_10(x/y)=10^whatever's on this side. Solve that way.

Answer 4

\[\log_{10}(6x-1)-\log_{10}(x-1)=1\]
\[\large10^{\log_{10}(6x-1)}-10^{\log_{10}(x-1)}=10^1\]
\[(6x-1)-(x-1)=10\]
\[6x-1-x+1=10\]
\[5x=10\]
\[x=\frac{10}{5}\]
\[x=2\]

Answer 5

okay so whenever a multiplication you do subtraction? I thought that was for addition and subtraction was division.