Question

(4a-3)=a+13/a+1 (4a-3)=a+13/a+1 @Mathematics

Answer 1

\[4a-3=\frac{a+13}{a+1}\]
yes?
Do you have any thoughts for an answer?

Answer 2

-1,1?

Answer 3

close, but not quite there :X

Answer 4

multiply both sides by a+1
\[(4a-3)(a+1)=a+13\]
expand using FOIL
\[4a^2+a-3=a+13\]
subtract a and 13 from both sides
\[4a^2-16=0\]
add 16 to both sides
\[4a^2=16\]
divide by 4
\[a^2=\frac{16}{4}\]
\[a^2=4\]
\[a=\pm\sqrt{4}\]
\[a=\pm 2\]
a= -2;2

Answer 5

i have no clue where im going wrong

Answer 6

oh the adding 16 to both sides

Answer 7

well, I can't see your work--but id say look carefully since ive given all of mine on these and try and figure it out :D

Answer 8

i subtracted 4-3