how do you find the y intercept and the vertical asymptotes step by step of
y=(4x)/(x^2-4) how do you find the y intercept and the vertical asymptotes step by step of
y=(4x)/(x^2-4) @Mathematics

Question

how do you find the y intercept and the vertical asymptotes step by step of 
y=(4x)/(x^2-4) how do you find the y intercept and the vertical asymptotes step by step of 
y=(4x)/(x^2-4) @Mathematics

amistre64 · Answer

the y intercept is always where the graph cross the y axis; and the value of x at the y axis is always 0

amistre64 · Answer

set x=0 to find the value for y

amistre64 · Answer

the verts are where the bottom goes bad; divide by zero is a vert

anonymous · Answer

ya but i need help with the algebra of actually solving the y int

amistre64 · Answer

if you factor top and bottom and whats left over after like terms cancel defines your verts

amistre64 · Answer

really?

y=4x/(x^2-4)

y=4.0/(0^2-4)

y=0/-4 = 0

anonymous · Answer

isnt that the x intercept?

amistre64 · Answer

.....no, that is the y intercept.  It just so happens that it is ALSO the x intercept since it crosses at the origin

amistre64 · Answer

but just set x=0 and solve for the y intercept; always.

anonymous · Answer

alright so how do you solve it setting y=0

amistre64 · Answer

a fraction is only zero when the top of it is zero, right?

amistre64 · Answer

so in this case when does 4x=0?

anonymous · Answer

ooooooooooooh alright thanks sorry I couldn't understand my teacher when she was explaining she made it sound a lot more complex

amistre64 · Answer

job security ;)