Question

solve for x
y=((2/5)x^2)+((14/10)x)+x^(2/5)
solve for x
y=((2/5)x^2)+((14/10)x)+x^(2/5)
@Mathematics

Answer 1

so you set it equal to 0 then solve for x

Answer 2

are you asking or telling that?

Answer 3

im asking

Answer 4

are you trying to find x-intercepts

Answer 5

not necessarily then, depends on what you need to know.

Answer 6

no this is the derivative of a function im trying to find max and min

Answer 7

take it away myininaya...

Answer 8

so this is the derivative of some function
do you want to write down the original function so we can check your derivative here?

Answer 9

or you know its right?

Answer 10

y = x^(2/5)((7/2)+x)

Answer 11

just incase there is a easier way that I missed

Answer 12

\[y'=\frac{2}{5}x^{\frac{2}{5}-1}(\frac{7}{2}+x)+x^\frac{2}{5}(0+1)\]

Answer 13

\[y'=\frac{2}{5}x^{\frac{-4}{5}}(\frac{7}{2}+x)+x^\frac{2}{5}\]

Answer 14

so that simplifies to (7(x+1))/5x^3/5 and then x=-1?

Answer 15

that should be x^(-3/5) where it is x^(-4/5) above

Answer 16

so X=-1 X=0

Answer 17

right?

Answer 18

or is it not x=0

Answer 19

\[y'=\frac{7}{5x^\frac{3}{5}}+\frac{2x}{5x^{\frac{3}{5}}}+x^\frac{2}{5}\]
right since turingtest knows how to subtract and i don't my bad

Answer 20

let myininaya do it, I'm eating and catching silly typos
I know you can subtract

Answer 21

\[y'=\frac{7+2x+5x}{x^\frac{3}{5}}\]

Answer 22

please though let me know if i make an error

Answer 23

\[y'=\frac{7(1+x)}{x^\frac{3}{5}}\]

Answer 24

critical numbers or x=-1, 0

Answer 25

looks good to me.

Answer 26

great i need to go to sleep now

Answer 27

g'night!

Answer 28

night

Answer 29

but 0 doesnt work

Answer 30

0 is in the domain of the the function f
f(0)=0