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if the roots of the equation (a2+b2)x2-2(ac+bd)x+(c2+d2)=0 are equal, prove that a/b=c/d
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if two roots are equal, b2-4ac=0, or (-2(ac+bd))^2 - 4 (a^2 + b^2) (c^2+d^2) = 0 or 4(ac)^2 + 8abcd + 4(bd)^2 - 4(ac)^2 - 4(ad)^2 - 4(bc)^2 - 4(bd)^2 = 0 or 8abcd -4(ad)^2 -4(bc)^2 = 0 or (ad)^2 - 2(ad)(bc) + (bc)^2 = 0 or (ad - bc)^2 = 0 or ad - bc = 0 or ad = bc therefore, a/b = c/d
thank you very much u r ginus
u dont need to say that...........just click on GOOD ANSWER that is ok...
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only one more question please
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find the are of circle x2+y2=a2 by integration
the answer is pi a^2 i have no idea if we can solve with integration........
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can u mail me on devil.magra@yahoo.com becoz i will loss my train
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