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Mathematics 7 Online
OpenStudy (anonymous):

Statistics A set of data is normally distributed with a mean of 200 and standard deviation of 50. What would be the standard score for a score of 100? What percentage of scores is between 200 and 100? What would be the percentile rank for a score of 100?

OpenStudy (anonymous):

mean=200 standard deviation=50

OpenStudy (anonymous):

100-200/50 -100/50 -2

OpenStudy (anonymous):

so does that make it -2.00, right.

OpenStudy (anonymous):

The table has: 0.4772

OpenStudy (amistre64):

since it just asks for the standard score; it only wants the z score itself and not any table value associated with it

OpenStudy (amistre64):

the next question asks for a percentage of scores tho

OpenStudy (anonymous):

oh ok. so z=-2

OpenStudy (amistre64):

correct; what is the value of P(100<X<200) ? and since 200 is the mean and you already found a zscore for 100 this is asking for the ztables value

OpenStudy (anonymous):

so the number I just gave is the answer to this one? the one out of the table.

OpenStudy (amistre64):

yep

OpenStudy (amistre64):

the percentile id have to read up on ...

OpenStudy (amistre64):

I know how to find a percentile from a given set of data points, just not sure how to do it from the curve

OpenStudy (amistre64):

got it; it should be the percent of area to the left of the zscore

OpenStudy (amistre64):

in other words P(X<100)

OpenStudy (anonymous):

i was just going to say do we need to find both P(x=100)(P(x=200)

OpenStudy (anonymous):

sorry to interrupt but when you get a chance could you help me out Amistre ?

OpenStudy (amistre64):

the percentile for the mean is just 50

OpenStudy (anonymous):

we are still on the second part right

OpenStudy (amistre64):

when i get a chance ill see what i can do

OpenStudy (anonymous):

this is our last one.

OpenStudy (amistre64):

the second part was the value you got from the ztable, its a measure of the area between the mean and 100

OpenStudy (amistre64):

which is what your ztable gives you anyways

OpenStudy (anonymous):

ok, just making sure I was on the right page, I wasn't lol!

OpenStudy (amistre64):

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