how would you evaluate 3a^2-2ab+c if a=-1 b=0 and c=11 please show work.
Just substitute a, b, and c in. 3(-1)^2 -2(-1)(0) + 11
what from there though??
Then use a calculator.
i have to show work though...
(-1)^2=?
= 3 + 0 + 11 = 14 (-1)^2?? >_<
(-1)^2=1 3(1)=3 -2(-1)(0)=0 so we have exactly what mimi has above
lols, i thought i was wrong xD
no i was trying to get c108 to answer some questions
well the answer is supposed to be 14 but i dont get how.
You don't get it >_< Just use a calculator then you will see. Infact, you can do it yourself, its easy just adding.
yeah, i dont get it. because you aren't explaining it...
Explanation isn't required. But I did explain to you, scroll up and see. Where are you stuck ? I dont get it.
i get it thanks.
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