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OpenStudy (anonymous):
how would you evaluate 3a^2-2ab+c if a=-1 b=0 and c=11 please show work.
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OpenStudy (mimi_x3):
Just substitute a, b, and c in.
3(-1)^2 -2(-1)(0) + 11
OpenStudy (anonymous):
what from there though??
OpenStudy (mimi_x3):
Then use a calculator.
OpenStudy (anonymous):
i have to show work though...
myininaya (myininaya):
(-1)^2=?
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OpenStudy (mimi_x3):
= 3 + 0 + 11
= 14
(-1)^2?? >_<
myininaya (myininaya):
(-1)^2=1
3(1)=3
-2(-1)(0)=0
so we have exactly what mimi has above
OpenStudy (mimi_x3):
lols, i thought i was wrong xD
myininaya (myininaya):
no
i was trying to get c108 to answer some questions
OpenStudy (anonymous):
well the answer is supposed to be 14 but i dont get how.
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OpenStudy (mimi_x3):
You don't get it >_<
Just use a calculator then you will see. Infact, you can do it yourself, its easy just adding.
OpenStudy (anonymous):
yeah, i dont get it. because you aren't explaining it...
OpenStudy (mimi_x3):
Explanation isn't required.
But I did explain to you, scroll up and see.
Where are you stuck ? I dont get it.
OpenStudy (anonymous):
i get it thanks.
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