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How long will it take for $2000 to double if it is invested at 13% interest compounded continuously?
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Assuming compounded pa, 4000 = 2000(1.13)^t Somebody verify this.
4000=2000(1.13)^t (2000(1.13)^t)/2000=4000/2000 (1.13)^t=2 2yrs
is that right?
2 is wrong. Its \[\log_{1.13} 2 \]
that is 5.67 years
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i dont understand how you got log1.13^2
its not 1.13^2 its base its like \[\log_{1.13} 2\]
1.13 is the base
|dw:1320203757253:dw|
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