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OpenStudy (anonymous):
3y to the 1/2+ y to the -1/2 3y to the 1/2+ y to the -1/2 @Mathematics
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OpenStudy (anonymous):
3y^(1/2)+y^-(1/2)= 3y^(1/2)+1/y^(1/2)..... Work this like any other fraction Multiply the first fraction by y^(1/2)/y^(1/2) which is one.... Then carry out the operation
OpenStudy (anonymous):
So what would the answer be cause Im getting something crazy
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