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Given cos0 = sqrt 3/ 2 and sin0 > 0, find sec0 (unit circle) Given cos0 = sqrt 3/ 2 and sin0 > 0, find sec0 (unit circle) @Mathematics
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sec(theta) = 1/cos(theta)
try and solve it using that..
So would it be \[\sqrt{3}/2\] ? I think I wrote that wrong
the inverse of that
sec is the inverse of cos
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that means that all you have to do is flip it
Ok thanks man. Guess my prof made an error like he always does because he has the same answer listed twice as a choice
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