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Mathematics 9 Online
OpenStudy (anonymous):

Given cos0 = sqrt 3/ 2 and sin0 > 0, find sec0 (unit circle) Given cos0 = sqrt 3/ 2 and sin0 > 0, find sec0 (unit circle) @Mathematics

OpenStudy (eyust707):

sec(theta) = 1/cos(theta)

OpenStudy (eyust707):

try and solve it using that..

OpenStudy (anonymous):

So would it be \[\sqrt{3}/2\] ? I think I wrote that wrong

OpenStudy (eyust707):

the inverse of that

OpenStudy (eyust707):

sec is the inverse of cos

OpenStudy (eyust707):

that means that all you have to do is flip it

OpenStudy (anonymous):

Ok thanks man. Guess my prof made an error like he always does because he has the same answer listed twice as a choice

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