Need answers to this question on Forces and Torques so that i can compare my solutions to yours.

You want to raise a wheel of mass m and radius r over a step of height h. To do so, you apply a horizontal force F. What is the magnitude of the force F so that the wheel just leaves the ground floor when the force is applied;

a) at the center of the wheel?

b) at the top of the wheel? @MIT 6.002 Circuit…

Question

Need answers to this question on Forces and Torques so that i can compare my solutions to yours.

You want to raise a wheel of mass m and radius r over a step of height h. To do so, you apply a horizontal force F. What is the magnitude of the force F so that the wheel just leaves the ground floor when the force is applied;

a) at the center of the wheel?

b) at the top of the wheel?       @MIT 6.002 Circuit…

anonymous · Answer

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anonymous · Answer

a. $$F(R-h)=Mg \sqrt{2Rh-h^{2}}$$ so 
$$F=(Mg \sqrt{2Rh-h^{2}})/(R-h)$$

b. $$F(2R-h)=Mg \sqrt{2Rh-h^{2}}$$ so $$F=(Mg \sqrt{2Rh-h^{2}})/(2R-h)$$