Question

Simplify.
Assume b, c ≠o.
(bc^3)^-3

Answer 1

= b^-3*c^-9

= 1 /( b^3c^9)

Answer 2

\[(bc^3)^{-3} = \frac{1}{(bc^3)^3} \rightarrow \frac{1}{b^3c^9}\] Now you explain yourself the different from zero, because it wouldn't make sense if it was zero since 1/0 is undefined.

Answer 3

ok so 1/b^3c^9 is the answer?

Answer 4

yup.

Answer 5

kk THX