Question

i need help finding the derivative of y=(t^2+3)*cubed root of t^2. i don't understand how to do it.

Answer 1

Using the product rule:
f(x)*g'(x) + g(x)*f'(x) where f(x) is t^2 + 3 and g(x) is cubed root of t^2 or in other terms: (t^2/3)

So that is
\[(t ^{2} + 3) \times ((2t ^{-1/3}) /3) + t ^{2/3} \times 2t\]

Answer 2

thank you so much! i wasn't sure which rule to use :)