Question

What is the equation in point-slope form of the line passing through (–2, 1) and (4, 13)? What is the equation in point-slope form of the line passing through (–2, 1) and (4, 13)? @Mathematics

Answer 1

slope:

m = (y2-y1)/(x2-x1)


m = (13-1)/(4-(-2))


m = (13-1)/(4+2)


m = 12/6


m = 2


So the slope is m = 2


Now turn to the point slope formula


y-y1 = m(x-x1)


and plug in m = 2, x1 = -2 and y1 = 1 to get


y-1 = 2(x-(-2))


y-1 = 2(x+2)


which is your answer