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jimthompson5910 (jim_thompson5910):
sure
OpenStudy (anonymous):
ax+b=cx-d;2x+9=7x-1
jimthompson5910 (jim_thompson5910):
what do you want to do here?
OpenStudy (anonymous):
I have no idea im lost
jimthompson5910 (jim_thompson5910):
I mean, are there any other instructions?
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OpenStudy (anonymous):
It says sole the literal equation for x. then use the solution to solve the sepcific equation
OpenStudy (anonymous):
solve sorry
OpenStudy (anonymous):
U there
jimthompson5910 (jim_thompson5910):
i see, so solve ax+b=cx-d to get
\[\Large ax+b=cx-d\]
\[\Large ax=cx-d-b\]
\[\Large ax-cx=-d-b\]
\[\Large x(a-c)=-d-b\]
\[\Large x=\frac{-d-b}{a-c}\]
In the case of the second equation 2x+9=7x-1, we see that a = 2, b = 9, c = 7 and d = 1, so plug all this info into the last equation to get
\[\Large x=\frac{-d-b}{a-c}\]
\[\Large x=\frac{-1-9}{2-7}\]
\[\Large x=\frac{-10}{-5}\]
\[\Large x=2\]
which is your answer
jimthompson5910 (jim_thompson5910):
does that make sense?
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OpenStudy (anonymous):
Yes thank you:) that was awesome i would of never guessed!
OpenStudy (anonymous):
5x+4y=10
jimthompson5910 (jim_thompson5910):
what about it?
OpenStudy (anonymous):
I need help writing the equation so that y is a function of x
jimthompson5910 (jim_thompson5910):
ok, Solve for y to get
\[\Large 5x+4y=10\]
\[\Large 4y=10-5x\]
\[\Large 4y=-5x+10\]
\[\Large y=\frac{-5x+10}{4}\]
\[\Large y=-\frac{5}{4}x+\frac{10}{4}\]
\[\Large y=-\frac{5}{4}x+\frac{5}{2}\]
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OpenStudy (anonymous):
Thats the answer
jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
alternatively, you can replace y with f(x) as they are the same thing to get \[\Large f(x)=-\frac{5}{4}x+\frac{5}{2}\]
jimthompson5910 (jim_thompson5910):
but the first answer is better in my opinion
OpenStudy (anonymous):
thanks what about......
18x-2y=26?
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jimthompson5910 (jim_thompson5910):
18x-2y=26
-2y=26-18x
-2y=-18x+26
y=(-18x+26)/(-2)
y=(-18x)/(-2)+26/(-2)
y = 9x - 13
OpenStudy (anonymous):
what about
4(2x-y)=6
jimthompson5910 (jim_thompson5910):
4(2x-y)=6
8x-4y=6
-4y=6-8x
-4y=-8x+6
y=(-8x+6)/(-4)
y=(-8x)/(-4)+(6)/(-4)
y=2x-3/2
So the answer is \[\Large y = 2x-\frac{3}{2}\]
OpenStudy (anonymous):
Ok this is easy 5x-3x=9?
jimthompson5910 (jim_thompson5910):
two x terms?
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OpenStudy (anonymous):
5x and 3x
jimthompson5910 (jim_thompson5910):
5x-3x = 9
2x = 9
x = 9/2
OpenStudy (anonymous):
3x+2y+5x=12 i dont get it/???
jimthompson5910 (jim_thompson5910):
3x+2y+5x=12
2y+8x=12
2y = -8x+12
y = -4x+6
OpenStudy (anonymous):
8x-8y=5
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OpenStudy (anonymous):
?
jimthompson5910 (jim_thompson5910):
solve for y and let me know what you get
jimthompson5910 (jim_thompson5910):
if you're stuck, the first step is to move the 8x to the other side
OpenStudy (anonymous):
x=5???
jimthompson5910 (jim_thompson5910):
8x-8y=5
-8y=5-8x ... subtract 8x from both sides
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jimthompson5910 (jim_thompson5910):
from there, rearrange terms and divide both sides by -8 to solve for y